algo meaning in English
阿尔戈
Examples
- On the basis of our lab ' s previous achievements , the author has studied three kinds of digital signal processing methods - the method based on a digital phase locked loop , the method based on quadrature demodulation , and the method based on adaptive funnel filter ( aff ) and sliding goertzel algo rithm ( sga ) . the author has also studied the cmf driving principle , various analog driving circuits , driving waves , and digital driving methods
主要研究了三种科氏流量计的数字信号处理方法：基于数字锁相环的方法、基于正交解调的方法和基于自适应funnel滤波器和滑动goertzel算法的方法；以及科氏流量计驱动的原理、各种模拟驱动的波形、电路以及数字驱动的方法等。 - In this article , we use idea of turning dispersion into convergence and put all the well ' s points into the same unit net to think about it . and answer three questions of the distribution of well drilling by the way of searching for groups of points . fincite - step - searching underthe condition of translationg fcoordinate system or revolving coordinate system . to first question . we find two algo - rithms and make use of data that is given to find the solution . we seek coorlinate of net point is co . 361 , 0 . 461 ) and mostly four old well ' s points are utilized at the same time by first algorithim , which are no . 2 , no , 4 , no . 5 , no . 10 . by second algorithm , we rechon the coordinate of net point is co . 390 , 0 . 505 ) . and that mostly four old well ' s points are utilizld which are no . 2 , no . 4 , no . 10 . to second question , we turn it into the first question by angling awt the center of net point . we seek that mostly six old well ' s points are utilized at the same time , which are no . 1 , no . 6 , no . 7 , no . 8 , no . 9 , no . 11 , when net is angled 0 . 78 radian . and net point is translated to ( 0 . 75 , 0 . 076 ) ( at nwe coordinate system ) . to third question , wefind a necessary and sufficient condition and affer algorithms , at last , we analyse algorithms
运用化分散为集中的思想,把所有的井点都放在同一个单位网格内考虑.在坐标可平移、旋转的条件下，利用寻找点群、有限步骤搜索法，对钻井布局的三个问题进行了解答.对问题一，给出了两个不同算法.并对题目提供的数据进行了求解，算法1得到的结点为（ 0 . 361 , 0 . 461 ） ,最多有4个旧井点被同时利用，它们是第2 、 4 、 5 、 10个井点;算法2得到的结点为( 0 . 390 , 0 . 505 ) ,最多有4个井点被利用,它们是第2 、 4 、 5 、 10个井点.对问题二，以结点为中心旋转一定的角度后，归结为问题一进行求解，求解结果为当网格倾斜角为0 . 78弧度（相对原坐标系） ，结点平移到（ 0 . 75 , 0 . 076 ）点(在新坐标系下) ，可被同时利用的最多旧井点为6个，它们是第1 、 6 、 7 、 8 、 9 、 11个井点，对问题三，我们给出了充要条件，并给出了算法.最后还分析了算法的优劣性