零质量的 meaning in English
zero mass
Examples
- According to goldstone theorem , the goldstone bosons with zero mass will emerge as the chiral symmetry is spontaneously broken
由goldstone理论可知，当手征自发破缺时会生成零质量的goldstone玻色子。 - In quantum chromodynamics ( qcd ) , vacuum is not trivial , that is , vacuum carry quantum numbers . such a behavior is embodied by non - perturbative con - densates of quarks and gluons . since hadrons are excitations with respect to the vacuum , hadronic properties are ultimately related to properties of the vacuum . based on the vacuum structure , some hadron properties have been described well . in the low energy region , qcd has two very important proper - ties : chiral symmetry spontaneous breaking and confinement , which are closely related to the vacuum characteristics of qcd . much experiments and theoretical studies have shown that chiral symmetry spontaneous breaking is very important to understand the low - energy feature of the strongly interacting physics , and the quark condensates give an expression to chiral symmetry spontaneous breaking . according to goldstone ' s theorem , the goldstone bosons with zero mass will emerge as the chiral symmetry is spontaneously broken . there are two ways : inear and non - linear methods to carry out this constraint . in our paper , we will use the non - linear method
大量实验和理论研究表明，手征对称自发破缺对于理解低能强相互作用十分重要，而夸克凝聚又是导致手征对称自发破缺的因素。按goldstone理论，伴随手征对称自发破缺应该会有零质量的goldstonebosons产生。而对于这一条件的实现有线性和非线性两种方法本文将用非线性的方法将手征对称自发破缺应用于su ( 3 )模型即重子八重态，得出描述其强相互作用的手征对称自发破缺lagrange密度。